省赛选拔赛——组队赛第二场

Rank 5。
2013年通化全国邀请赛的题。比赛时出了2道题,打完之后才知道杭电G++编译器有问题,D题同样的代码C++能AC,G++一直超时。一开始A题交了好久次才过罚
时好多,一着急就乱了,改一个地方就提交,这个必须改。
A:HDU 4493
给出12个月的工资,求平均薪水,貌似是因为数据大和浮点数精度问题WA了好几次,最后用long long过的。

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#include<cstdio>
#include<cmath>
using namespace std;
typedef long long LL;
int main(){
int t;
scanf("%d",&t);
while(t--){
LL sum=0;
LL tmp1,tmp2;
for(int i=0;i<12;++i){
scanf("%I64d.%I64d",&tmp1,&tmp2);
sum+=tmp1*100;
sum+=tmp2;
}
sum=(LL)floor((double)sum/12.0+0.5);
printf("$%I64d",sum/100);
sum%=100;
if(sum!=0){
if(sum%10) printf(".%02I64d",sum);
else printf(".%I64d",sum/10);
}
printf("\n");
}
return 0;
}

D:HDU 4496
判断连通块个数,倒着做一遍并查集,然后计数储存就好了。比赛时G++编译器超时,赛后用C++补过。

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#include<cstdio>
using namespace std;
const int maxn=10010;
int n,m,p[maxn];
int u[maxn*10],v[maxn*10],ans[maxn*10];
inline int findx(int x){
return p[x]==x?x:p[x]=findx(p[x]);
}
int main(){
while(~scanf("%d%d",&n,&m)){
for(int i=0;i<m;++i) scanf("%d%d",&u[i],&v[i]);
int cnt=0;
for(int i=0;i<n;++i) p[i]=i;
for(int i=m-1;i>=0;--i){
if((ans[i]=n-cnt)==1) continue;
int x=findx(u[i]),y=findx(v[i]);
if(x!=y) {++cnt,p[x]=y;}
}
for(int i=0;i<m;++i) printf("%d\n",ans[i]);
}
return 0;
}

H:HDU 4597
博弈问题,有两堆牌,每次可以从堆顶或堆底拿一张,两人都足够聪明,求先手最大得分。DP解决,因为状态没找好,所以直接分类讨论了。赛后看了学长代码重写了一遍。

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重写后的:
#include<iostream>
#include<algorithm>
#include<cstring>
using namespace std;
const int maxn=22;
int n,a[maxn],b[maxn];
int d[maxn][maxn][maxn][maxn];
int dp(int l1,int r1,int l2,int r2,int sum){
int& k=d[l1][r1][l2][r2];
if(k!=-1) return k;
if(l1<=r1){
k=max(k,sum-dp(l1+1,r1,l2,r2,sum-a[l1]));
k=max(k,sum-dp(l1,r1-1,l2,r2,sum-a[r1]));
}
if(l2<=r2){
k=max(k,sum-dp(l1,r1,l2+1,r2,sum-b[l2]));
k=max(k,sum-dp(l1,r1,l2,r2-1,sum-b[r2]));
}
return max(0,k);
}
int main(){
int t;
cin>>t;
while(t--){
memset(d,-1,sizeof(d));
cin>>n;
int sum=0;
for(int i=1;i<=n;++i) cin>>a[i],sum+=a[i];
for(int i=1;i<=n;++i) cin>>b[i],sum+=b[i];
cout<<dp(1,n,1,n,sum)<<endl;
}
return 0;
}
原代码:
#include<iostream>
#include<algorithm>
#include<cstring>
using namespace std;
const int maxn=22;
const int inf=1<<30;
int d[maxn][maxn][maxn][maxn],a[maxn],b[maxn];
int dp(int i,int j,int i2,int j2){
int &k=d[i][j][i2][j2];
if(k!=-1) return k;
if(!(i-i2)&&!(j-j2)) return k=0;
if(!(i-i2)){
if(j-j2==1) return k=b[j];
return k=max(min(dp(i,j-2,i2,j2),dp(i,j-1,i2,j2+1))+b[j],min(dp(i,j,i2,j2+2),dp(i,j-1,i2,j2+1))+b[j2+1]);
}
if(!(j-j2)){
if(i-i2==1) return k=a[i];
return k=max(min(dp(i-2,j,i2,j2),dp(i-1,j,i2+1,j2))+a[i],min(dp(i-1,j,i2+1,j2),dp(i,j,i2+2,j2))+a[i2+1]);
}
if(i-i2==1&&j-j2==1) return k=max(a[i],b[j]);
if(i-i2==1){
int cur=0;
cur=max(cur,min(dp(i-1,j-1,i2,j2),dp(i-1,j,i2,j2+1))+a[i]);
{
int ccur=inf;
ccur=min(ccur,dp(i-1,j-1,i2,j2));
ccur=min(ccur,dp(i,j-2,i2,j2));
ccur=min(ccur,dp(i,j-1,i2,j2+1));
cur=max(cur,ccur+b[j]);
}
{
int ccur=inf;
ccur=min(ccur,dp(i-1,j,i2,j2+1));
ccur=min(ccur,dp(i,j-1,i2,j2+1));
ccur=min(ccur,dp(i,j,i2,j2+2));
cur=max(cur,ccur+b[j2+1]);
}
return k=cur;
}
if(j-j2==1){
int cur=0;
cur=max(cur,min(dp(i-1,j-1,i2,j2),dp(i,j-1,i2+1,j2))+b[j]);
{
int ccur=inf;
ccur=min(ccur,dp(i-1,j-1,i2,j2));
ccur=min(ccur,dp(i-1,j,i2+1,j2));
ccur=min(ccur,dp(i-2,j,i2,j2));
cur=max(cur,ccur+a[i]);
}
{
int ccur=inf;
ccur=min(ccur,dp(i-1,j,i2+1,j2));
ccur=min(ccur,dp(i,j-1,i2+1,j2));
ccur=min(ccur,dp(i,j,i2+2,j2));
cur=max(cur,ccur+a[i2+1]);
}
return k=cur;
}
int cur=0;
{
int ccur=inf,ci=i-1;
ccur=min(ccur,dp(ci-1,j,i2,j2));
ccur=min(ccur,dp(ci,j-1,i2,j2));
ccur=min(ccur,dp(ci,j,i2+1,j2));
ccur=min(ccur,dp(ci,j,i2,j2+1));
cur=max(cur,ccur+a[i]);
}
{
int ccur=inf,cj=j-1;
ccur=min(ccur,dp(i-1,cj,i2,j2));
ccur=min(ccur,dp(i,cj-1,i2,j2));
ccur=min(ccur,dp(i,cj,i2+1,j2));
ccur=min(ccur,dp(i,cj,i2,j2+1));
cur=max(cur,ccur+b[j]);
}
{
int ccur=inf,ci2=i2+1;
ccur=min(ccur,dp(i-1,j,ci2,j2));
ccur=min(ccur,dp(i,j-1,ci2,j2));
ccur=min(ccur,dp(i,j,ci2+1,j2));
ccur=min(ccur,dp(i,j,ci2,j2+1));
cur=max(cur,ccur+a[i2+1]);
}
{
int ccur=inf,cj2=j2+1;
ccur=min(ccur,dp(i-1,j,i2,cj2));
ccur=min(ccur,dp(i,j-1,i2,cj2));
ccur=min(ccur,dp(i,j,i2+1,cj2));
ccur=min(ccur,dp(i,j,i2,cj2+1));
cur=max(cur,ccur+b[j2+1]);
}
return k=cur;
}
int main(){
ios::sync_with_stdio(false);
int t;
cin>>t;
while(t--){
memset(d,-1,sizeof(d));
int n;
cin>>n;
for(int i=1;i<=n;++i) cin>>a[i];
for(int i=1;i<=n;++i) cin>>b[i];
cout<<dp(n,n,0,0)<<endl;
}
return 0;
}

本文迁移自我的 CSDN博客 ,格式可能有所偏差。